Answer (1 of 3): You may require the following quanties of steel reinforcements per one cum of cement concrete which is expressed in kg:- 1.Column footings 75 kg use 10 or 12 mm dia rods 2.Grade beams 100kg use 12,16 mm dia rods -85%; 8 and 6mmdia rods -15% 3.Plinth beams 125 kg use 8mm dia ro...

Answer (1 of 13): Quantity of steel is not dependent on the volume of concrete, but on the structure where it is being used. Slabs: 0.7 to 1.0%, Beams: 1% to 2%, Columns: 1% to 5% It may vary depending upon the loading condition as well For Example Lets take example of RCC Column, where reinfo...

Jun 06, 2020· Quantity of steel in concrete depending on type of structure and load of structure. For Foundation :- 0.5 to 0.8 % steel are required; Let we take minimum 0.5 % of steel is required on 1 m3 concrete. Then quantity of steel. = (0.5/100)×1× 7850 = 39.25 kg

Jan 26, 2018· Tags: concrete reinforcement ratio table, estimation and cost analysis, Estimation and Costing, How do I calculate quantity of steel in R.C.C slab/column/beam, how many kg of steel in 1 cubic meter, how much steel required for 1 cubic meter concrete, how to calculate quantity of steel and cement from drawing, how to calculate steel in rcc slab ...

Jun 19, 2014· For example, according to SP (Russian norms for Nonprestressed Concrete Structures) minimum reinforcement area should be determined Asmin = mus * b * h0, where Asmin - is the minimum area of reinforcing steel within the tensile zone, mus - is the minimum reinforcement ratio, for bending mus =0.001, for bending with axial force mus =0.0025, b ...

Maximum quantity of steel required for 1m3 concrete beam is 2%, now 2% of 1m3 = 0.02m3, and we know that 1m3 steel weight is 7850 Kg, so weight of 0.02m3 steel = 0.02 × 7850 = 157 kg, so maximum quantity of steel required for 1m3 concrete beam is 157 Kg. Quantity of steel required for 1m3 concrete Column. Thumb rule for steel in slab = 2% to 4%

In civil engineering the thumb rule for Steel to Concrete ratio is 100:130. The ratio means for every 130 kg concrete 100 kg of steel is needed. 100 kg of steel strengthen the structure in RCC. Failing this ratio of steel to concrete would cause weakening the structure and fatal cracks to it.

Density of concrete = 2400 kg/cum. So, 1 bag of cement produces = 400/2400 = 0.167 cum. No. of bags required for 01 cum of concrete = 1/0.167 = 5.98 bags ~ 6 bags. From above, if the concrete mix is 1:2:4 , to get a cubic meter of concrete we require. 1.Cement = 6 bags = 300 kgs. 2.Fine Aggregate = 115/0.167 = 689 kg

3. Estimate total length of stirrup which is equal to stirrup cutting length times number of stirrups. 4. Convert that length into kilograms or Tons. This can be done by multiplying cross section area of steel by its total length by density of steel which 7850 kg/m 3. Total steel quantity of column equal to the sum of both main and stirrup steels.

How much cement required for M10 concrete in Kgs step 5:- calculate cement required for 1 cubic metre of M10 concrete in Kgs ( kilogram) is equal to = 1/10 × 1.54 m3 × 1440 Kg/m3 = 222 Kgs. Ans. :- 222 Kgs quantity of cement required for 1 cubic metre of M10 concrete. How many cement bags required for M10 concrete

Aug 03, 2018· Now we start calculation to find Cement, Sand and Aggregate quality in 1 cubic meter concrete. CALCULATION FOR CEMENT QUANTITY; Cement= (1/5.5) x 1.54 = 0.28 m 3 ∴ 1 is a part of cement, 5.5 is sum of ratio Density of Cement is 1440/m 3 = 0.28 x 1440 = 403.2 kg We know each bag of cement is 50 kg

May 15, 2014· well , reinforcement steel required for slab is nearly 0.7 to 0.8% of the volume of concrete so if concrete is 1 cum then steel will be 1*0.7/100 =0.007 but density of steel is 7850 kg/ cum so 0.007*7850=54.95 say 55 kg per cum so steel required to reinforce 1 cum concrete for slab is approximately 55 kgs.

Considering concrete density = 2400 kg/cum, One bag of cement and other ingredients can produce = 400/2400 = 0.167 Cum of concrete (1:2:4) 01 bag cement yield = 0.167 cum concrete with a proportion of 1:2:4. 01 cum of concrete will require. Cement required = 1/0.167 = 5.98 Bags ~ 6 Bags. Sand required = 115/0.167 = 688 Kgs or 14.98 cft

Jun 19, 2014· For example, according to SP (Russian norms for Nonprestressed Concrete Structures) minimum reinforcement area should be determined Asmin = mus * b * h0, where Asmin - is the minimum area of reinforcing steel within the tensile zone, mus - is the minimum reinforcement ratio, for bending mus =0.001, for bending with axial force mus =0.0025, b ...

In the special civil engineering article, it will be guided in what way to compute Steel quantity for each M³ for Lintel, Slab, Beam, Foundation and Column. Least/Minimum steel percentage is equal to 0.7 percent. Steel Quantity is equal to [0.7/100] x 1 is equal to 0.007 m 3 Steel Weight is equal to 0.007 x 7850 is equal to 54.95 ≊ 55 kg/m 3

ex: When material 1 above is concrete and material 2 is steel: to transform steel into concrete concrete steel E E E E n 1 2 to find the neutral axis of the equivalent concrete member we transform the width of the steel by multiplying by n to find the moment of inertia of the equivalent concrete member, I transformed, use the new geometry ...

The deformed Reinforcing Steel Bar is supplied in length of 9m or 12 m as common sizes. The steel bar diameter applied is different and accordingly the weight varies. We are listing theoretical unit weight list of commonly used wire gauge below for your reference. Deformed steel …

Lets take example of RCC Column, where reinforcement required is 2.5% of concrete volume, weight of steel required will be: =196.25 kg. 2. Labour Requirement for 1m 3 of RCC: Labours required are presented in terms of days required by particular labour to complete its work for the given quantity of concrete. Following are the various labours ...

0.016. Note: (1) Theoretical weight calculation formula of rebar: theoretical weight (kg/m) = 0.00617 × D² (where, D is the section diameter, unit: mm) (2) The density is calculated as 7.85g/cm³; (3) The theoretical weight of hot-rolled ribbed bars, cold-rolled ribbed bars, HRB335, HRB400, HRB500 and other deformed bars of different ...

It is also referred to "density in place". Conventional concrete has density between 1900 kg/m 3 and 2400 kg/m 3 and can endure, on day 28 of its pouring, and has a compressive strength between 2500 psi and 7000 psi (pounds per square inch) ~ 200-492 kg/cm 2.

As per the guidelines are given in the BN Dutta reference book the steel quantity of slab is 1% of the total volume of concrete utilized. Thumb rule to estimate Steel quantity of above slab = Volume of Concrete x Density of Steel x % of Steel of Member. Steel weight required for above slab = …

0.016. Note: (1) Theoretical weight calculation formula of rebar: theoretical weight (kg/m) = 0.00617 × D² (where, D is the section diameter, unit: mm) (2) The density is calculated as 7.85g/cm³; (3) The theoretical weight of hot-rolled ribbed bars, cold-rolled ribbed bars, HRB335, HRB400, HRB500 and other deformed bars of different ...

It is also referred to "density in place". Conventional concrete has density between 1900 kg/m 3 and 2400 kg/m 3 and can endure, on day 28 of its pouring, and has a compressive strength between 2500 psi and 7000 psi (pounds per square inch) ~ 200-492 kg/cm 2.

As per the guidelines are given in the BN Dutta reference book the steel quantity of slab is 1% of the total volume of concrete utilized. Thumb rule to estimate Steel quantity of above slab = Volume of Concrete x Density of Steel x % of Steel of Member. Steel weight required for above slab = …

Portland cement is the most common type of cement in general usage. It is a basic ingredient of concrete, mortar, and many plasters. British masonry worker Joseph Aspdin patented Portland cement in 1824. It was named because of the similarity of its color to Portland limestone, quarried from the English Isle of Portland and used extensively in London architecture.

Sep 24, 2017· L is the total length of steel bars of which weight is to be calculated. For example: if we have to calculate the weight of 10 mm steel bars, then we will proceed as follow: W=10^2/ 162. W=0.617 kg/meter. In this way we will get steel bars weight per meter.

petroleum refining at 6.5%, steel production at 1.8% and wood production at 0.5%.5 • According to EPA, between 900 and 1100 kg (1984 and 2425 lbs) of CO2 is emitted for every 1000 kg (2205 lbs) of portland cement produced in the U.S. This depends on the fuel type, raw ingredients used and the energy efficiency of the cement plant.6

concrete beams and prestressed concrete beams for which limited test data are available. In this work, a theoretical approach for the minimum steel ratios that are required for the ductile behaviour at failure in bending, shear and torsion, in concrete beams made of concrete with different strengths is presented.

Jul 26, 2018· STEEL QUANTITY: Weight of bar in kg/meter should be calculated as (d 2 ÷ 162) where‘d’ is the diameter of bar in mm. ‘L’ for column main steel in footing should be considered as minimum 30cm/as specified. For bent up bar add 0.42d in straight length of …

Jul 29, 2011· It also depends on the load that the concrete has to take at certain points. 7865kg is the weight of a cubic meter of steel. Typical examples; A pile cap could contain 400kg/m3 A heavy duty industrial slab or structure could contain 200kg-400kg/m3 A footpath could contain 40kg/m3 (all depends on the design, but numbers above should give you a ...

Concrete Basics. Portland Cement Association. "Density in Place: Density of normal CLSM in place typically ranges from 90 to 125 pounds per cubic foot (1840 to 2320 kg/cubic m)." 2320 kg/m 3. (conventional) Conversion Factors, Material Properties and Constants, Edward Boyden, MIT. "Density Concrete 2242 kg/m^3". 2242 kg/m 3.

Enter your post and hole dimensions in any units. The calculator will give you the results in cubic yards and the number of pre-mixed bags of concrete (40 lb, 60 lb, and 80 lb bags). To ensure that your posts are sturdy for a long time to come, remember to make your holes three times the diameter of your post and 1 ⁄ 3 as deep as your fence.

blocks = wall sq ft block sq ft. If you’re using a standard 16″ x 8″ x 8″ block, find the number of blocks needed by dividing the wall square footage by 0.89. blocks = wall sq ft 0.89. We recommend adding 5%-10% additional blocks to account for broken blocks or blocks that need to be cut for the edges.

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